Opencv从入门到放弃---5.银行卡识别案例(OpenCV = open(开源)+ c(ctrl c)+ v(ctrl v))

Belle ·
更新时间:2024-09-20
· 883 次阅读

别人都是信用卡识别,我这里换成银行卡识别,甚至换成身份证,其实是一个原理,找到和银行卡数字匹配的字体,修改识别数字区域的宽和高,都能识别出来,原理就是根据模板数字进行匹配

银行卡识别案例1.前期准备2.对模板图像进行预处理操作3.对信用卡进行处理 # 导入工具包 # opencv读取图片的格式为b g r # matplotlib图片的格式为 r g b import numpy as np import cv2 from imutils import contours import matplotlib.pyplot as plt %matplotlib inline 1.前期准备 # 信用卡的位置 predict_card = "data/nongye.png" # 模板的位置 template = "data/jianshedemo.png" # 指定信用卡类型 FIRST_NUMBER = { "3": "American Express", "4": "Visa", "5": "MasterCard", "6": "Discover Card", "7":"中国建设银行" } # 定义一些功能函数 # 对框进行排序 def sort_contours(cnts, method="left-to-right"): reverse = False i = 0 if method == "right-to-left" or method == "bottom-to-top": reverse = True if method == "top-to-bottom" or method == "bottom-to-top": i = 1 boundingBoxes = [cv2.boundingRect(c) for c in cnts] #用一个最小的矩形,把找到的形状包起来x,y,h,w (cnts, boundingBoxes) = zip(*sorted(zip(cnts, boundingBoxes), key=lambda b: b[1][i], reverse=reverse)) return cnts, boundingBoxes # 调整图片尺寸大小 def resize(image, width=None, height=None, inter=cv2.INTER_AREA): dim = None (h, w) = image.shape[:2] if width is None and height is None: return image if width is None: r = height / float(h) dim = (int(w * r), height) else: r = width / float(w) dim = (width, int(h * r)) resized = cv2.resize(image, dim, interpolation=inter) return resized # 定义cv2展示函数 def cv_show(name,img): cv2.imshow(name,img) cv2.waitKey(0) cv2.destroyAllWindows() 2.对模板图像进行预处理操作 # 读取模板图像 img = cv2.imread(template) cv_show("img",img) plt.imshow(img)

image-20200510144913062

# 转灰度图 ref = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY) cv_show("ref",ref) plt.imshow(ref)

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#转化为二值图 ref = cv2.threshold(ref,10,255,cv2.THRESH_BINARY_INV)[1] cv_show("ref",ref) plt.imshow(ref)

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#cv2.findContours()函数接受的参数为二值图,即黑白的(不是灰度图),cv2.RETR_EXTERNAL只检测外轮廓,cv2.CHAIN_APPROX_SIMPLE只保留终点坐标 #返回的list中每个元素都是图像中的一个轮廓 # 在二值化后的图像中计算轮廓 ref,refCnts,hierarchy = cv2.findContours(ref.copy(),cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE) # 在原图上画出轮廓 cv2.drawContours(img,refCnts,-1,(0,0,255),3) cv_show("img",img) plt.imshow(img)

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print(np.array(refCnts).shape) # 排序,从左到右,从上到下 refCnts = sort_contours(refCnts,method="left-to-right")[0] digits = {} # 遍历每一个轮廓 for (i, c) in enumerate(refCnts): # 计算外接矩形并且resize成合适大小 (x, y, w, h) = cv2.boundingRect(c) roi = ref[y:y + h, x:x + w] roi = cv2.resize(roi, (57, 88)) # 每一个数字对应每一个模板 digits[i] = roi

image-20200510145617149

3.对信用卡进行处理 # 初始化卷积核 rectKernel = cv2.getStructuringElement(cv2.MORPH_RECT, (9, 3)) sqKernel = cv2.getStructuringElement(cv2.MORPH_RECT, (5, 5)) # 读取信用卡 image = cv2.imread(predict_card) cv_show("image",image) plt.imshow(image)

image-20200510145845026

# 对图像进行预处理操作 # 先对图像进行resize操作 image = resize(image,width=300) # 灰度化处理 gray = cv2.cvtColor(image,cv2.COLOR_BGR2GRAY) cv_show("gray",gray) plt.imshow(gray)

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# 对图像礼帽操作 # 礼帽 = 原始输入-开运算结果 # 开运算:先腐蚀,再膨胀 # 突出更明亮的区域 tophat = cv2.morphologyEx(gray,cv2.MORPH_TOPHAT,rectKernel) cv_show("tophat",tophat) plt.imshow(tophat)

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# 用Sobel算子边缘检测 gradX = cv2.Sobel(tophat, ddepth=cv2.CV_32F, dx=1, dy=0, ksize=-1) gradX = np.absolute(gradX) (minVal, maxVal) = (np.min(gradX), np.max(gradX)) gradX = (255 * ((gradX - minVal) / (maxVal - minVal))) gradX = gradX.astype("uint8") print (np.array(gradX).shape) cv_show("gradX",gradX) plt.imshow(gradX)

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# 对图像闭操作 # 闭操作:先膨胀,再腐蚀 # 可以将数字连在一起 gradX = cv2.morphologyEx(gradX, cv2.MORPH_CLOSE, rectKernel) cv_show("gradX",gradX) plt.imshow(gradX)

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#THRESH_OTSU会自动寻找合适的阈值,适合双峰,需把阈值参数设置为0 thresh = cv2.threshold(gradX, 0, 255,cv2.THRESH_BINARY | cv2.THRESH_OTSU)[1] cv_show("thresh",thresh) plt.imshow(thresh)

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# 再进行一次闭操作 thresh = cv2.morphologyEx(thresh, cv2.MORPH_CLOSE, sqKernel) #再来一个闭操作 cv_show("thresh",thresh) plt.imshow(thresh)

image-20200510150408418

# 计算轮廓 nouse,threshCnts, hierarchy = cv2.findContours(thresh.copy(), cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE) cnts = threshCnts cur_img = image.copy() cv2.drawContours(cur_img,cnts,-1,(0,0,255),3) cv_show("img",cur_img) plt.imshow(cur_img) # print(cnts)

image-20200510150504457

locs = [] # 遍历轮廓 for (i, c) in enumerate(cnts): # 计算矩形 (x, y, w, h) = cv2.boundingRect(c) ar = w / float(h) # 选择合适的区域,根据实际任务来,这里的基本都是四个数字一组 if ar > 2.5 and ar 20 and w 10 and h < 30): #符合的留下来 locs.append((x, y, w, h)) print(x,y,w,h) # 将符合的轮廓从左到右排序 locs = sorted(locs, key=lambda x:x[0])

image-20200510150555477

output = [] # 模板匹配 # 遍历每一个轮廓中的数字 for (i, (gX, gY, gW, gH)) in enumerate(locs): # initialize the list of group digits groupOutput = [] # 根据坐标提取每一个组 group = gray[gY - 5:gY + gH + 5, gX - 5:gX + gW + 5] cv_show("group",group) # 预处理 group = cv2.threshold(group, 0, 255,cv2.THRESH_BINARY | cv2.THRESH_OTSU)[1] cv_show("group",group) # 计算每一组的轮廓 _,digitCnts,hierarchy = cv2.findContours(group.copy(), cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE) digitCnts = contours.sort_contours(digitCnts,method="left-to-right")[0] # 计算每一组中的每一个数值 for c in digitCnts: # 找到当前数值的轮廓,resize成合适的的大小 (x, y, w, h) = cv2.boundingRect(c) roi = group[y:y + h, x:x + w] roi = cv2.resize(roi, (57, 88)) cv_show("roi",roi) # 计算匹配得分 scores = [] # 在模板中计算每一个得分 for (digit, digitROI) in digits.items(): # 模板匹配 result = cv2.matchTemplate(roi, digitROI,cv2.TM_CCOEFF) (_, score, _, _) = cv2.minMaxLoc(result) scores.append(score) # 得到最合适的数字 groupOutput.append(str(np.argmax(scores))) # 画出来 cv2.rectangle(image, (gX - 5, gY - 5),(gX + gW + 5, gY + gH + 5), (0, 0, 255), 1) cv2.putText(image, "".join(groupOutput), (gX, gY - 15),cv2.FONT_HERSHEY_SIMPLEX, 0.65, (0, 0, 255), 2) # 得到结果 output.extend(groupOutput) # 打印结果 print("Credit Card Type: {}".format(FIRST_NUMBER[output[0]])) print("Credit Card #: {}".format("".join(output))) cv_show("Image",image) plt.imshow(image)

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开源 银行 opencv ctrl

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