注:可以给我充话费~
import re
# r 原生字符串 避免掉干扰
def checkPhone(number):
# 18434766698
# pat = r'1[35789]\d{9}$'
# pat = r'1([35789]\d)|(47)\d{8}$'
pat = r'1(([35789]\d)|(47))\d{8}$'
res = re.match(pat,number)
print(res)
checkPhone('18434766698')
checkPhone('12345678977')
checkPhone('14745678977')
实现注释
# 注释 /* part1 */ /* part2 */
import re
str1 = '/* part1 */ /* part2 */'
# /*代表不转义 正则表达时会被转义
print(re.findall('//*.*/*/',str1))
print(re.findall('//*.*?/*/',str1))
提取指定字符串
# 需求:提取 fqx ... man
"""
*? +? X? 最小匹配
(?:x) 类似(xyz)但不表示一组
"""
import re
str1 = 'fqx is a good man ! fqx is a nice man ! fqx is a very headsome man!'
print('~~~~~贪婪匹配~~~~~~~')
print(re.findall('fqx.*man',str1))
print('~~~~~非贪婪匹配~~~~~~~')
print(re.findall('fqx.*?man', str1))
作者:暧昧忆故人