使用Python编写一个简单的tic-tac-toe游戏的教程

Halima ·
更新时间:2024-11-01
· 680 次阅读

 这个教程,我们将展示如何用python创建一个井字游戏。 其中我们将使用函数、数组、if条件语句、while循环语句和错误捕获等。

首先我们需要创建两个函数,第一个函数用来显示游戏板:
 

def print_board(): for i in range(0,3): for j in range(0,3): print map[2-i][j], if j != 2: print "|", print ""

这我们使用两个for循环来遍历map,该map是一个包含了位置信息的二维数组。

游戏板看起来是这样的:
 

| | | | | | X | X | O | X | O | O | X X | X | X X | X | X X | X | X

 
下面我们需要一个函数check_done()来检查游戏是否结束。如果结束,则返回True并打印消息。
 

def check_done(): for i in range(0,3): if map[i][0] == map[i][1] == map[i][2] != " " \ or map[0][i] == map[1][i] == map[2][i] != " ": print turn, "won!!!" return True if map[0][0] == map[1][1] == map[2][2] != " " \ or map[0][2] == map[1][1] == map[2][0] != " ": print turn, "won!!!" return True if " " not in map[0] and " " not in map[1] and " " not in map[2]: print "Draw" return True return False

有几个地方需要检查,首先检查水平和垂直方向,是否有一行或一列不为空且包含有三个相同的符号,然后我们再检查斜方向。如果上面有一个方向满足,游戏结束并打印“Won!!!”。请注意检查变量改变,它用来标记当前是哪一位玩家。

同时我们需要检查当前游戏板是否被填满且没有人获胜,游戏平局。

有了上面的两个函数,下面我们创建3个变量:
 

turn = "X" map = [[" "," "," "], [" "," "," "], [" "," "," "]] done = False

    turn : 轮到谁
    map : 游戏板
    done : 游戏是否结束

现在启动游戏:
 

while done != True: print_board() print turn, "'s turn" print moved = False while moved != True:

这里使用了while循环直到游戏结束并返回true.在这个循环里面,使用了另外一个while循环来检查玩家是否移动,如果玩家没有移动,则程序会跳到下一次循环。

下一步告诉玩家怎么玩:
 

print "Please select position by typing in a number between 1 and 9, see below for which number that is which position..." print "7|8|9" print "4|5|6" print "1|2|3" print try: pos = input("Select: ") if pos <=9 and pos >=1:

我们期望玩家输入一个数字,检查该数字是否是在1到9之间。另外,我们这里需要一段错误处理逻辑,我们还需要需要检查玩家是否能移动到一个位置:
 

Y = pos/3 X = pos%3 if X != 0: X -=1 else: X = 2 Y -=1

以下是全部的代码:
 

def print_board(): for i in range(0,3): for j in range(0,3): print map[2-i][j], if j != 2: print "|", print "" def check_done(): for i in range(0,3): if map[i][0] == map[i][1] == map[i][2] != " " \ or map[0][i] == map[1][i] == map[2][i] != " ": print turn, "won!!!" return True if map[0][0] == map[1][1] == map[2][2] != " " \ or map[0][2] == map[1][1] == map[2][0] != " ": print turn, "won!!!" return True if " " not in map[0] and " " not in map[1] and " " not in map[2]: print "Draw" return True return False turn = "X" map = [[" "," "," "], [" "," "," "], [" "," "," "]] done = False while done != True: print_board() print turn, "'s turn" print moved = False while moved != True: print "Please select position by typing in a number between 1 and 9,\ see below for which number that is which position..." print "7|8|9" print "4|5|6" print "1|2|3" print try: pos = input("Select: ") if pos <=9 and pos >=1: Y = pos/3 X = pos%3 if X != 0: X -=1 else: X = 2 Y -=1 if map[Y][X] == " ": map[Y][X] = turn moved = True done = check_done() if done == False: if turn == "X": turn = "O" else: turn = "X" except: print "You need to add a numeric value" 您可能感兴趣的文章:Python编程中的反模式实例分析Python实现拼接多张图片的方法python字符串替换的2种方法



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