利用C语言实现五子棋游戏

Zada ·

更新时间:2024-11-10

· 1915 次阅读

本文实例为大家分享了C语言实现五子棋游戏的具体代码，供大家参考，具体内容如下

一、前言

本文将先介绍五子棋运行所需要的函数，最后串联成完整代码。

我们需要实现的功能有：1.菜单menu函数

2.初始化棋盘Initboard函数

3.显示棋盘Displayboard函数

4.实现人机、人人模式的选择

5.落子函数 playermove computermove

6.判断输赢ifwin函数

先来看看运行效果吧！

二、头文件


#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#include<time.h>
#include<stdlib.h>
#include<windows.h>
#define ROW 10  //定义棋盘的宽
#define COL 10  //定义棋盘的长
                //定义常量方便全局的修改
void Initboard(char board[ROW][COL], int row, int col);
//初始化棋盘
void Displayboard(char board[ROW][COL], int row, int col);
//展示棋盘
void Playermove_1(char board[ROW][COL], int row, int col,int*px,int *py);
//玩家一下棋
void Playermove_2(char board[ROW][COL], int row, int col,int*px, int *py);
//玩家二下棋
void computermove(char board[ROW][COL], int row, int col);
//电脑下棋
void game1(char board[ROW][COL], int row, int col);
//人机模式
void game2(char board[ROW][COL], int row, int col);
//人人模式
int Ifwin(char board[ROW][COL], int row, int col, int x, int y);
//判断输赢
int check_x(char board[ROW][COL], int row, int col, int x, int y);
//判断竖直五子
int check_y(char board[ROW][COL], int row, int col, int x, int y);
//判断水平五子
int check_xy_up(char board[ROW][COL], int row, int col, int x, int y);
//判断斜上五子
int check_xy_down(char board[ROW][COL], int row, int col, int x, int y);
//判断斜下五子

三、menu菜单函数


void menu()
{   //完成菜单的初始化
 printf("***********************\n");
 printf("***********************\n");
 printf("*****1.play  0.exit****\n");
 printf("***********************\n");
 printf("***********************\n");
 printf("请输入：");
}

很简单，就不多说了

四、初始化棋盘Initboard函数

初始化棋盘，为数组一一存入空格


void Initboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   board[i][j] = ' ';
  }
 }
}

五、显示棋盘Displayboard函数

打印简单的方格线，并打印数据内容


void Displayboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (j = 0; j < col; j++)//打印横向y坐标
 {
  if (j == 0)//考虑到x轴所占的一格
  {
   printf("  %d  ", j + 1);
  }
  else
  {
   printf(" %d  ", j + 1);
  }
 }
 printf("\n");
 for (i = 0; i < row; i++)//打印数据
 {
  for (j = 0; j < col; j++)
  {
   if (j == 0)//顺带打印竖向x坐标
   {
    printf("%2d",i+1);//%md表示域宽为m
    printf("  %c ",board[i][j]);
   }
   else
   {
    printf(" %c ", board[i][j]);
   }
   if (j < col - 1)
    printf("|");
  }
  printf("\n");
  //打印分割行
  if (i < row - 1)
  {
   for (j = 0; j < col; j++)
   {
    if (j == 0)//同样考虑到y轴
     printf("   ---");
    else
     printf("---");
    if (j < col - 1)
     printf("|");
   }
   printf("\n");
  }
 }
}

六、落子函数

玩家一落子——playermove_1


void Playermove_1(char board[ROW][COL], int row, int col, int *px, int*py)//ROW可以省，COL不行
{
 int x = *px;
 int y = *py;
 while (1)
 {
  if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性
  {
   if (board[x -1][y- 1] == ' ')//保证落子点为空
   {        
    board[x-1 ][y -1] = '*';
    *px = x; *py = y;//如果开始xy输入不合法，则要对外部xy修改，所以选择传址操作
    break;
   }
   else
   {
    printf("你不能在此处落子\n");
    printf("玩家1落子，请重新输入x y坐标： ");
    scanf("%d%d", &x, &y);
   }
  }
  else
  {
   printf("输入坐标不合法\n");
   printf("玩家落子，请重新输入x y坐标： ");
   scanf("%d%d", &x, &y);
  }
 }
}

玩家2落子完全相同，就不赘叙了

电脑落子


void computermove(char board[ROW][COL], int row, int col)
{
 int x = 0;
 int y = 0;
    //rand函数的使用需要srand函数的初始化，但srand不可以被重复调用，所以放在外部
 while (1)
 {
  x = rand() % ROW;
  y = rand() % COL;
  if (board[x][y] == ' ')//x的范围在0~row-1，所以这里x不用-1了
  {
   board[x][y] = '#';
   break;
  }
 }
}

七、判断输赢ifwin

根据我们下五子棋的经验，能获胜的地方必定是最后落子的水平线、竖直线、和两个斜对角线，我们只需对其进行检索即可。ifwin的返回值决定之后的switch语句

弱弱的说一句，虽然看起来多，但很多都是重复的。


int Ifwin(char board[ROW][COL], int row, int col, int x, int y)
{
 int ret;
 {
  ret = check_x(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_y(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_xy_up(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_xy_down(board, row, col, x, y);
  if (ret >= 5)
   return 0;
 }
  return 3;
}
int check_x(char board[ROW][COL], int row, int col, int x, int y)//检查x轴竖直方向
{
 int sum = 1;
 int old_x = x;
 while (x < row  && board[x - 1][y - 1] == board[x][y - 1])
 {
  sum++;
  x++;
 }
 x = old_x;
 while (x-2>= 0 && board[x - 1][y - 1] == board[x - 2][y - 1] )
 {
  sum++;
  x--;
 }
 return sum;
}
int check_y(char board[ROW][COL], int row, int col, int x, int y)//检查y轴水平方向
{
 int sum = 1;
 int old_y = y;
 while (y<col && board[x-1][y-1] == board[x-1][y]  )
 {
  sum++;
  y++;
 }
 y = old_y;
 while (y-2 >= 0 && board[x-1][y-1] == board[x-1][y -2]  )
 {
  sum++;
  y--;
 }
 return sum;
}
int check_xy_up(char board[ROW][COL], int row, int col, int x, int y)//检查斜上45度
{
 int sum = 1;
 int old_x = x;
 int old_y = y;
 while (x<row &&  y - 2 >= 0 && board[x - 1][y - 1] == board[x][y - 2])
 {
  sum++;
  x++;
  y--;
 }
 x = old_x;
 y = old_y;
 while (x - 2 >= 0 && y <col && board[x - 1][y - 1] == board[x - 2][y])
 {
  sum++;
  x--;
  y++;
 }
 return sum;
}
int check_xy_down(char board[ROW][COL], int row, int col, int x, int y)//检查斜下45度
{
 int sum = 1;
 int old_x = x;
 int old_y = y;
 while (x<row && y <col && board[x - 1][y - 1] == board[x][y])
 {
  sum++;
  x++;
  y++;
 }
 x = old_x;
 y = old_y;
 while (board[x-1][y-1] == board[x -2][y-2 ] && x-2>=0  && y-2 >=0)
 {
  sum++;
  x--;
  y--;
 }
 return sum;
}

八、人机、人人模式的选择

初始选择界面


void game()
{
 int input;
 char board[ROW][COL] = { 0 };
 Initboard(board, ROW, COL);
 //初始化棋盘
 Displayboard(board, ROW, COL);
 //展示棋盘
 printf("请选择模式：1.人机；2.玩家对战\n");
 printf("请选择：");
 do{
  scanf("%d", &input);
  printf("\n");
  switch (input)
  {
  case 1:printf("游戏模式1开始!（注意：竖为x轴，横为y轴）\n");  game1(board, ROW, COL); break;
  case 2:printf("游戏模式2开始!（注意：竖为x轴，横为y轴）\n"); ; game2(board, ROW, COL); break;
  default:printf("请重新输入\n"); break;
  }
 } while (input != 1 && input != 2);//do while语句在输入错误时反复输入
}

game1的具体实现


void game1(char board[ROW][COL], int row, int col)
{
 srand((unsigned int)time(NULL));//srand只要设置一次就可以，所以要放在while循环外
 while (1)
 {
  int ret;
  int count = 0;
  int flag = 0;
  //判读玩家的下棋
  int x; int y;
  printf("玩家落子，请依次输入x y坐标： ");
  scanf("%d%d", &x, &y);
  Playermove_1(board, row, col,&x, &y);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)//全下满则认为平局
   ret = 1;
  else 
      ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("玩家获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)//用flag跳出while循环
   break;
  //判断计算机的下棋
  computermove(board, row, col);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)
   ret = 1;
  else
   ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("电脑获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)
   break;
 }
}

作者觉得写的是挺啰嗦，欢迎留言建议。game2和game1玩家一的内容很相近，就不赘述

九、作者遇到的坑点

1.输入的坐标和存在数组里的下标有减一的关系，在写的时候不要写忘记了

2.传址操作才能改变函数外的变量值

十、完整的代码

头文件就省了


int main()
{
 int input;
 do{
  system("cls");//清屏
  menu();
  scanf("%d", &input);
  switch (input)
  {
  case 1:
   printf("游戏开始\n\n");  game(); break;
  case 0:
   printf("退出游戏\n"); break;
  default:
   printf("请重新输入\n"); break;
  }
  Sleep(3000);//暂停3秒
 } while (input);//do while语句实现可以反复玩
 return 0;
} 
void menu()
{   //完成菜单的初始化
 printf("***********************\n");
 printf("***********************\n");
 printf("*****1.play  0.exit****\n");
 printf("***********************\n");
 printf("***********************\n");
 printf("请输入：");
}
void Initboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < row; i++)
 {
  for (j = 0; j < col; j++)
  {
   board[i][j] = ' ';
  }
 }
}
void Displayboard(char board[ROW][COL], int row, int col)
{
 int i = 0;
 int j = 0;
 for (j = 0; j < col; j++)//打印横向y坐标
 {
  if (j == 0)//考虑到x轴所占的一格
  {
   printf("  %d  ", j + 1);
  }
  else
  {
   printf(" %d  ", j + 1);
  }
 }
 printf("\n");
 for (i = 0; i < row; i++)//打印数据
 {
  for (j = 0; j < col; j++)
  {
   if (j == 0)//顺带打印竖向x坐标
   {
    printf("%2d",i+1);//%md表示域宽为m
    printf("  %c ",board[i][j]);
   }
   else
   {
    printf(" %c ", board[i][j]);
   }
   //数字表示坐标
   if (j < col - 1)
    printf("|");
  }
  printf("\n");
  //打印分割行
  if (i < row - 1)
  {
   for (j = 0; j < col; j++)
   {
    if (j == 0)//同样考虑到y轴
     printf("   ---");
    else
     printf("---");
    if (j < col - 1)
     printf("|");
   }
   printf("\n");//别忘记这里也要换行
  }
 }
}
void game()
{
 int input;
 char board[ROW][COL] = { 0 };
 Initboard(board, ROW, COL);
 //初始化棋盘
 Displayboard(board, ROW, COL);
 //展示棋盘
 printf("请选择模式：1.人机；2.玩家对战\n");
 printf("请选择：");
 do{
  scanf("%d", &input);
  printf("\n");
  switch (input)
  {
  case 1:printf("游戏模式1开始!（注意：竖为x轴，横为y轴）\n");  game1(board, ROW, COL); break;
  case 2:printf("游戏模式2开始!（注意：竖为x轴，横为y轴）\n"); ; game2(board, ROW, COL); break;
  default:printf("请重新输入\n"); break;
  }
 } while (input != 1 && input != 2);//do while语句在输入错误时反复输入
}
void game1(char board[ROW][COL], int row, int col)
{
 srand((unsigned int)time(NULL));//srand只要设置一次就可以，所以要放在while循环外
 while (1)
 {
  int ret;
  int count = 0;
  int flag = 0;
  //判读玩家的下棋
  int x; int y;
  printf("玩家落子，请依次输入x y坐标： ");
  scanf("%d%d", &x, &y);
  Playermove_1(board, row, col,&x, &y);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)//全下满则认为平局
   ret = 1;
  else 
      ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("玩家获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)//用flag跳出while循环
   break;
  //判断计算机的下棋
  computermove(board, row, col);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)
   ret = 1;
  else
   ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("电脑获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)
   break;
 }
}
void game2(char board[ROW][COL], int row, int col)
{
 while (1)
 {
  int ret;
  int count = 0;
  int flag = 0;
  int x; int y;
  //判读玩家1的下棋
  printf("玩家1落子，请输入坐标:（注意：竖为x轴，横为y轴）");
  scanf("%d%d", &x, &y);
  Playermove_1(board, row, col, &x, &y);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)
   ret = 1;
  else
   ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("玩家1获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)
   break;
  //判断玩家2的下棋
  printf("玩家2落子，请输入坐标:（注意：竖为x轴，横为y轴）");
  scanf("%d%d", &x, &y);
  Playermove_2(board, row, col, &x, &y);
  count++;
  Displayboard(board, ROW, COL);
  if (count == ROW*COL)
   ret = 1;
  else
   ret = Ifwin(board, ROW, COL, x, y);
  switch (ret)
  {
  case 0:printf("玩家2获胜\n"); flag = 1; break;
  case  1:printf("平局\n"); flag = 1; break;
  default: break;
  }
  if (flag == 1)
   break;
 }
}
void Playermove_1(char board[ROW][COL], int row, int col, int *px, int*py)//ROW可以省，COL不行
{
 int x = *px;
 int y = *py;
 while (1)
 {
  if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性
  {
   if (board[x -1][y- 1] == ' ')//保证落子点为空
   {        
    board[x-1 ][y -1] = '*';
    *px = x; *py = y;//如果开始xy输入不合法，要对外部xy修改，所以要传址操作
    break;
   }
   else
   {
    printf("你不能在此处落子\n");
    printf("玩家1落子，请重新输入x y坐标： ");
    scanf("%d%d", &x, &y);
   }
  }
  else
  {
   printf("输入坐标不合法\n");
   printf("玩家落子，请重新输入x y坐标： ");
   scanf("%d%d", &x, &y);
  }
 }
}
void Playermove_2(char board[ROW][COL], int row, int col, int *px, int*py)
{
 int x = *px;
 int y = *py;
 while (1)
 {
  if (x >= 1 && x <= row && y >= 1 && y <= col)//判断输入坐标的合法性
  {
   if (board[x - 1][y - 1] == ' ')//保证落子点为空
   {
    board[x - 1][y - 1] = '#';
    *px = x; *py = y;
    break;
   }
   else
   {
    printf("你不能在此处落子\n");
    printf("玩家2落子，请重新输入x y坐标： ");
    scanf("%d%d", &x, &y);
   }
  }
  else
  {
   printf("输入坐标不合法\n");
   printf("玩家落子，请重新输入x y坐标： ");
   scanf("%d%d", &x, &y);
  }
 }
}
void computermove(char board[ROW][COL], int row, int col)
{
 int x = 0;
 int y = 0;
 while (1)
 {
  x = rand() % ROW;
  y = rand() % COL;
  if (board[x][y] == ' ')
  {
   board[x][y] = '#';
   break;
  }
 }
}
int Ifwin(char board[ROW][COL], int row, int col, int x, int y)
{
 int ret;
 {
  ret = check_x(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_y(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_xy_up(board, row, col, x, y);
  if (ret >= 5)
   return 0;
  ret = check_xy_down(board, row, col, x, y);
  if (ret >= 5)
   return 0;
 }
  return 3;
}
int check_x(char board[ROW][COL], int row, int col, int x, int y)//检查x轴竖直方向
{
 int sum = 1;
 int old_x = x;
 while (x < row  && board[x - 1][y - 1] == board[x][y - 1])
 {
  sum++;
  x++;
 }
 x = old_x;
 while (x-2>= 0 && board[x - 1][y - 1] == board[x - 2][y - 1] )
 {
  sum++;
  x--;
 }
 return sum;
}
int check_y(char board[ROW][COL], int row, int col, int x, int y)//检查y轴水平方向
{
 int sum = 1;
 int old_y = y;
 while (y<col && board[x-1][y-1] == board[x-1][y]  )
 {
  sum++;
  y++;
 }
 y = old_y;
 while (y-2 >= 0 && board[x-1][y-1] == board[x-1][y -2]  )
 {
  sum++;
  y--;
 }
 return sum;
}
int check_xy_up(char board[ROW][COL], int row, int col, int x, int y)//检查斜上45度
{
 int sum = 1;
 int old_x = x;
 int old_y = y;
 while (x<row &&  y - 2 >= 0 && board[x - 1][y - 1] == board[x][y - 2])
 {
  sum++;
  x++;
  y--;
 }
 x = old_x;
 y = old_y;
 while (x - 2 >= 0 && y <col && board[x - 1][y - 1] == board[x - 2][y])
 {
  sum++;
  x--;
  y++;
 }
 return sum;
}
int check_xy_down(char board[ROW][COL], int row, int col, int x, int y)//检查斜下45度
{
 int sum = 1;
 int old_x = x;
 int old_y = y;
 while (x<row && y <col && board[x - 1][y - 1] == board[x][y])
 {
  sum++;
  x++;
  y++;
 }
 x = old_x;
 y = old_y;
 while (board[x-1][y-1] == board[x -2][y-2 ] && x-2>=0  && y-2 >=0)
 {
  sum++;
  x--;
  y--;
 }
 return sum;
}

如果对你有帮助和启发，作者感到很高兴。

五子棋游戏五子棋 C语言

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