C++ 基础编程之十进制转换为任意进制及操作符重载

Ethel ·

更新时间:2024-11-14

· 748 次阅读

最近学习C++ 的基础知识，完成十进制转换为任意进制及操作符重载，在网上找的不错的资料，这里记录下，

实例代码：


#include<iostream> 
#include<vector> 
#include<limits> 
using namespace std; 
using std::iterator; 
///<summary> 
///十进制转换为任意进制，为了熟悉操作符，也加了操作符重载。 
///包括自增（++），运算符重（+），赋值函数重载（=）,输出符（<<） 
///</summary> 
class TenToAny 
{ 
  vector<char> value; 
  long long _n; 
  long long _x; 
public: 
  TenToAny():_n(10),_x(0) 
  {   
  } 
  void Switch() 
  { 
    try 
    { 
      int x=_x, n=_n; 
      char flag=' '; 
      if(x>LONG_MAX||x<LONG_MIN) 
        throw "溢出"; 
      if(x<0) 
      { 
        flag='-'; 
        x=-x; 
      } 
      while(x!=0) 
      { 
        long long remain = x%n; 
         x = x/n; 
        if(remain>=10) 
          remain = 'A'+ remain % 10; 
        else  
          remain +='0'; 
        value.push_back(remain); 
      } 
      vector<char>::reverse_iterator v= value.rbegin(); 
      while(*v=='0') 
        value.pop_back(); 
      if(flag=='-') 
        value.push_back(flag); 
    } 
    catch(char *e) 
    { 
      cout<<e<<endl; 
    } 
  } 
  TenToAny(long long n,long long x) 
  { 
    _n=n; 
    _x=x; 
    Switch(); 
  } 
  TenToAny &operator = (const TenToAny &num) 
  { 
    if(this==&num) 
      return *this; 
    value=num.value; 
    _n=num._n; 
    _x=num._x; 
    return *this; 
  } 
  TenToAny operator +(const TenToAny &num1) 
  { 
    TenToAny num; 
    num._x=num1._x + _x; 
    num._n=num1._n; 
    num.Switch(); 
    return num; 
  } 
  TenToAny &operator ++()//前置++ 
  { 
    _x++; 
    value.clear(); 
    this->Switch(); 
    return *this; 
  } 
  TenToAny &operator ++(int)//后置++ 
  { 
    TenToAny *temp=new TenToAny(this->_n,this->_x); 
    _x++; 
    value.clear(); 
    this->Switch(); 
    return *temp; 
  } 
  friend ostream &operator <<(ostream &out,TenToAny num); 
}; 
ostream &operator <<(ostream &out,TenToAny num) 
{ 
  vector<char> value =num.value; 
  vector<char>::reverse_iterator v= value.rbegin(); 
  for(;v!=value.rend();v++) 
  { 
    out<<*v; 
  } 
  return out; 
} 
int main() 
{ 
  TenToAny num(19,111); 
  TenToAny copy(19,222); 
  TenToAny sum; 
  sum =num+copy; 
  cout<<num<<endl; 
  cout<<copy<<endl; 
  cout<<copy++<<endl; 
  cout<<(++copy)<<endl; 
  return 0; 
}

运行结果：