Python ldap实现登录实例代码

An ·
更新时间:2024-09-21
· 726 次阅读

下面一段代码是小编给大家介绍的Python ldap实现登录实例代码,一起看看吧

ldap_config = { 'ldap_path': 'ldap://xx.xx.xx.xx:389', 'base_dn': 'ou=users,dc=ledo,dc=com', 'ldap_user': 'uid=reporttest,ou=users,dc=ledo,dc=com', 'ldap_pass': '111111.0', 'original_pass': '111111.0' } ldap_message = { 0: 0, #'ok' 1: 1, #'用户名或密码错误' 2: 2, #ldap验证异常' } import ldap import base64 import hashlib from config_message import ldap_config, ldap_message class LDAP_API(object): _ldap_path = ldap_config['ldap_path'] _base_dn = ldap_config['base_dn'] _ldap_user = ldap_config['ldap_user'] _ldap_pass = ldap_config['ldap_pass'] _original_pass = ldap_config['original_pass'] # 连接ldap服务器 def __init__(self): try: self.ldapconn = ldap.initialize(self._ldap_path) self.ldapconn.protocal_version = ldap.VERSION3 self.ldapconn.simple_bind(self._ldap_user, self._ldap_pass) except ldap.LDAPError, e: print e # 验证用户登录 def ldap_check_login(self, username, password): obj = self.ldapconn searchScope = ldap.SCOPE_SUBTREE # searchFilter = '(&(cn='+username+')(userPassword='+password+'))' searchFilter = 'uid=' + username try: obj.search(self._base_dn, searchScope, searchFilter, None) # id--2 # 将上一步计算的id在下面运算 result_type, result_data = obj.result(2, 0) if result_type != ldap.RES_SEARCH_ENTRY: return {'status': ldap_message[1], 'data': ''} dic = result_data[0][1] l_realname = dic['sn'][0] l_password = dic['userPassword'][0] md_password = LDAP_API.hash_md5(password) if l_password in (password, md_password): return {'status': ldap_message[0], 'data': l_realname} else: return {'status': ldap_message[1], 'data': ''} except ldap.LDAPError, e: return {'status': ldap_message[2], 'data': ''} @staticmethod def hash_md5(data): md = hashlib.md5() md.update(str(data)) a = md.digest() b = '{MD5}' + base64.b64encode(a) return b 您可能感兴趣的文章:Python_LDA实现方法详解



ldap Python

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