python模拟实现分发扑克牌

Bonita ·

更新时间:2024-09-21

· 734 次阅读

本文实例为大家分享了python分发扑克牌的具体代码，供大家参考，具体内容如下

52张扑克牌发个4个玩家，每人13张。

要求：

自动生成一幅扑克牌组；洗牌；发牌到玩家手中；将玩家手中扑克牌按花色大小整理好。

思路一


import random
import operator
def auto():
  pokers=[]
  poker=[]
  for i in ['♥','♠','♦','♣']:
    for j in ['A','2','3','4','5','6','7','8','9','10','J','Q','K']:
      poker.append(i)
      poker.append(j)
      pokers.append(poker)
      poker=[]
  return pokers
poker=auto()
random.shuffle(poker)
li={}
for k in ['player1','player2','player3','player4']:
  b=random.sample(poker,13)  
  for s in b:
    poker.remove(s)
  li.setdefault(k,b)    
print('player1：',sorted(li['player1'],key=operator.itemgetter(0,1)))
print('player2：',sorted(li['player2'],key=operator.itemgetter(0,1)))  
print('player3：',sorted(li['player3'],key=operator.itemgetter(0,1)))
print('player4：',sorted(li['player4'],key=operator.itemgetter(0,1)))

思路二


import random
import time
A=['♥','♠','♦','♣']
B=['A','2','3','4','5','6','7','8','9','10','J','Q','K']
poker=[]
pokers=[]
n=1
for i in A:
  for j in B:
     pokers.append((n,(i+j)))
     n=n+1
print("开始洗牌....")
random.shuffle(pokers)
def xipai(x):
  for i in x:
    pokers.remove(i)
  return pokers
def fapai(y):
  for i in y:
    print(i[1],',',end=" ")
def paixu(z):
  for i in z:
    print(i[1],',',end=" ")
time.sleep(3)
a=random.sample(pokers,13) 
pokers=xipai(a)  
print("开始给player1发牌：\n")
print(fapai(a))
b=random.sample(pokers,13) 
pokers=xipai(b)  
print("开始给player2发牌：\n")
print(fapai(b))
c=random.sample(pokers,13) 
pokers=xipai(c)  
print("开始给player3发牌：\n")
print(fapai(c))
d=random.sample(pokers,13) 
pokers=xipai(d)  
print("开始给player4发牌：\n")
print(fapai(d))
a.sort()
b.sort()
c.sort()
d.sort()
time.sleep(3)
print("player1的牌：\n")
print(paixu(a))
print("player2的牌：\n")
print(paixu(b))
print("player3的牌：\n")
print(paixu(c))
print("player4的牌：\n")
print(paixu(d))

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扑克牌 Python

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