whirlpool密码哈希算法(c语言实现)

Pamela ·
更新时间:2024-09-21
· 894 次阅读

whirlpool密码哈希算法(c语言实现)
本人为在校大学生,所写代码有诸多不足,希望各位多多指正。编译器为Dev C++
其中,明文与密钥可变换。 #include using namespace std; //明文 char M[10000]="abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz"; //分组数据 int a[64],b[64],c[64],d[64]={0}; //密钥,赋值的为K[0]这个赋值便是算法中的密钥K int Ktmp[64],K[11][64]={{1,1,3,1,5,8,9,5,5,1,1,3,1,5,8,9,9,5,1,1,3,1,5,8,8,9,5,1,1,3,1,5,5,8,9,5,1,1,3,1,1,5,8,9,5,1,1,3,3,1,5,8,9,5,1,1,1,3,1,5,8,9,5,1}}; //θ变换用到的数组C int C[64]={1,1,3,1,5,8,9,5, 5,1,1,3,1,5,8,9, 9,5,1,1,3,1,5,8, 8,9,5,1,1,3,1,5, 5,8,9,5,1,1,3,1, 1,5,8,9,5,1,1,3, 3,1,5,8,9,5,1,1, 1,3,1,5,8,9,5,1}; //S盒 int S[256]={0x68,0x10,0xeb,0x2b,0x48,0x9d,0x6a,0xe4, 0xe3,0xa3,0x56,0x81,0x7d,0xf1,0x85,0x93, 0x2c,0x8e,0x78,0xca,0x17,0xa9,0x61,0xd5, 0x5d,0x0b,0x8c,0x3c,0x77,0x51,0x22,0x42, 0x3f,0x54,0x41,0x80,0xcc,0x86,0xb3,0x18, 0x2e,0x57,0x06,0x62,0xf4,0x36,0xd1,0x6b, 0x1b,0x65,0x75,0x10,0xda,0x49,0x26,0xf9, 0xcb,0x66,0xe7,0xba,0xae,0x50,0x52,0xab, 0x05,0xf0,0x0d,0x73,0x3b,0x04,0x20,0xfe, 0xdd,0xf5,0xb4,0x5f,0x0a,0xb5,0xc0,0xa0, 0x71,0xa5,0x2d,0x60,0x72,0x93,0x39,0x08, 0x83,0x21,0x5c,0x87,0xb1,0xe0,0x00,0xc3, 0x12,0x91,0x8a,0x02,0x1c,0xe6,0x45,0xc2, 0xc4,0xfd,0xbf,0x44,0xa1,0x4c,0x33,0xc5, 0x84,0x23,0x7c,0xb0,0x25,0x15,0x35,0x69, 0xff,0x94,0x4d,0x70,0xa2,0xaf,0xcd,0xd6, 0x6c,0xb7,0xf8,0x09,0xf3,0x67,0xa4,0xea, 0xec,0xb6,0xd4,0xd2,0x14,0x1e,0xe1,0x24, 0x38,0xc6,0xdb,0x4b,0x7a,0x3a,0xde,0x5e, 0xdf,0x95,0xfc,0xaa,0xd7,0xce,0x07,0x0f, 0x3d,0x58,0x9a,0x98,0x9c,0xf2,0xa7,0x11, 0x7e,0x8b,0x43,0x03,0xe2,0xdc,0xe5,0xb2, 0x4e,0xc7,0x6d,0xe9,0x27,0x40,0xd8,0x37, 0x92,0x8f,0x01,0x1d,0x53,0x3e,0x59,0xc1, 0x4f,0x32,0x16,0xfa,0x74,0xfb,0x63,0x9f, 0x34,0x1a,0x2a,0x5a,0x8d,0xc9,0xcf,0xf6, 0x90,0x28,0x88,0x9b,0x31,0x0e,0xbd,0x4a, 0xe8,0x96,0xa6,0x0c,0xc8,0x79,0xbc,0xbe, 0xef,0x6e,0x46,0x97,0x5b,0xed,0x19,0xd9, 0xac,0x99,0xa8,0x29,0x64,0x1f,0xad,0x55, 0x13,0xbb,0xf7,0x6f,0xb9,0x47,0x2f,0xee, 0xb8,0x7b,0x89,0x30,0xd3,0x7f,0x76,0x82 }; // 第n组明文转换为整形 void code(int n,int a[64],int b[64],int s=64) { for(int i=0;i<s;i++) { a[i]=int(M[64*(n-1)+i]); a[i]=a[i]&0x000000ff; } } //γ变换 void Gamma(int a[64],int b[64]) { for(int i=0;i<64;i++) { b[i]=a[i]=a[i]&0x000000ff; a[i]=S[b[i]]; } } //列循环变换,π变换 void PI(int a[64],int b[64]) { for(int i=0;i<8;i++) { for(int j=0;j<8;j++)a[j*8+i]=b[((j-i)%8)*8+i]; } } //线性扩散变换,θ变换 void Theta(int a[64],int b[64]) { for(int i=0;i<8;i++) { for(int j=0;j<8;j++) { a[8*i+j]=0; for(int k=0;k<8;k++)a[8*i+j]+=b[8*i+k]*C[8*k+j]; } } } //密钥加法, σ[k] void Sigma(int n,int a[64],int b[64]) { for(int i=0;i<64;i++) { a[i]=b[i]^K[n][i]; } } //保持a,b数组相同 void same(int a[64],int b[64]) { for(int i=0;i<64;i++) { b[i]=a[i]; } } //整体加密函数W,其中包含轮函数ρ void Rho(int a[64],int b[64]) { same(a,c); Sigma(0,a,b); same(a,b); for(int i=1;i<=10;i++) { Gamma(a,b); same(a,b); PI(a,b); same(a,b); Theta(a,b); same(a,b); Sigma(i,a,b); same(a,b); } for(int i=0;i<64;i++)a[i]=b[i]^c[i]^d[i]; same(a,d); } //密钥拓展 void extension() { for(int i=1;i<=10;i++) { same(K[i-1],Ktmp); same(K[i-1],K[i]); Gamma(a,b); same(a,b); PI(K[i],Ktmp); same(K[i],Ktmp); Theta(K[i],Ktmp); same(K[i],Ktmp); for(int j=0;j<8;j++)K[i][j]=Ktmp[j]^S[8*(i-1)+j]; for(int j=8;j256则无法补充256bit的 明文长度,需要多添加一个分组,下面两个函数即为两种情况 int extendsion1(unsigned long len,unsigned long n) { int x=len%64; code(n-1,a,b,x); a[x]=128; for(int i=x+1;i<32;i++)a[i]=0; for(int i=0;i<32;i++) { //进行移位操作时需要注意,移位位数不能超过被处理数据所占bit数,如果溢出则无法得到想要结果,这里使用循环每次移位8bit unsigned long q=len; for(int j=0;j>8; a[63-i]=q&0x000000ff; } } int extendsion2(unsigned long len,unsigned long n) { int x=len%64; code(n-2,a,b,x); a[x]=128; for(int i=x+1;i<64;i++)a[i]=0; same(a,c); for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); Rho(a,b); for(int i=0;i<32;i++)a[i]=0; for(int i=0;i<32;i++) { unsigned long q=len; for(int j=0;j>8; a[63-i]=q&0x000000ff; } } int main(int argc, char *argv[]) { unsigned long len=strlen(M);//先计算,明文字符串长度 int P=((len%64)<32)?1:0;//判断使用哪种填充方式 unsigned long n=(P==1)?(len/64+1):(len/64+2); extension();//进行密钥拓展 if(P==1)//进行判断,如果P=1那么,len%64<32不需要额外拓展一个分组 { for(int i=1;i<=n-1;i++) { code(i,a,b); //进行a[i]&0x000000ff的目的是将高于8bit的数据置为0,以免影响输出 for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); same(a,c); Rho(a,b); } extendsion1(len,n); for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); same(a,b); same(a,c); Rho(a,b); } else { for(int i=1;i<=n-2;i++) { code(i,a,b); for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); same(a,c); Rho(a,b); } extendsion2(len,n); for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); same(a,b); same(a,c); Rho(a,b); } cout<<endl; for(int i=0;i<64;i++)a[i]=a[i]&0x000000ff; for(int i=0;i<64;i++)printf("%02x",a[i]); return 0; }

最后附上运行截图,输出为转为整型的扩展后的明文数据,以及最后输出的哈希值,输出格式限制为2位16进制,即每个字节为单位输出,输出两位16进制数。
在这里插入图片描述


作者:Ezyyz



哈希算法 哈希 C语言 算法

需要 登录 后方可回复, 如果你还没有账号请 注册新账号