python+Tkinter+多线程的实例

Raissa ·
更新时间:2024-09-20
· 42 次阅读

目录

python+Tkinter+多线程

tkinter与多线程问题

总结

python+Tkinter+多线程

界面和多线程一向是编程里比较难的地方,常见的做法一般是界面一个线程,后台新开一个工作线程,这两个线程进行通信,这样可以让界面不至于为响应。

在python中可以利用队列完成整体的架构设计。

直接给大家看代码吧,一个简单实例,非常好的例子。

import Tkinter,time,threading,random,Queue class GuiPart(): def __init__(self,master,queue,endCommand): self.queue=queue Tkinter.Button(master,text='Done',command=endCommand).pack() def processIncoming(self): while self.queue.qsize(): try: msg=self.queue.get(0) print msg except Queue.Empty: pass class ThreadedClient(): def __init__(self,master): self.master=master self.queue=Queue.Queue() self.gui=GuiPart(master,self.queue,self.endApplication) self.running=True self.thread1=threading.Thread(target=self.workerThread1) self.thread1.start() self.periodicCall() def periodicCall(self): self.master.after(200,self.periodicCall) self.gui.processIncoming() if not self.running: self.master.destroy() def workerThread1(self): #self.ott=Tkinter.Tk() #self.ott.mainloop() while self.running: time.sleep(rand.random()*1.5) msg=rand.random() self.queue.put(msg) def endApplication(self): self.running=False rand=random.Random() root=Tkinter.Tk() client=ThreadedClient(root) root.mainloop() tkinter与多线程问题

长时间执行后台任务,UI会处于无响应状态。在子线程里更新UI状态,听说是不允许的。在哪个线程里调用了tk.mainloop(),就只能在哪个线程里更新UI。

下例演示了如何更新。

import Tkinter as tk from ttk import * import time import Queue, threading class MainWindow: def __init__(self): self.root = tk.Tk() self.root.title('Demo') def show(self): self.progress = tk.IntVar() self.progress_max = 100 self.progressbar = Progressbar(self.root, mode='determinate', orient=tk.HORIZONTAL, variable=self.progress, maximum=self.progress_max) self.progressbar.pack(fill=tk.BOTH, expand=True, padx=5, pady=5) self.progress.set(0) btn = tk.Button(self.root, text='start', command=self.start) btn.pack(fill=tk.BOTH, expand=True, padx=15, pady=5) self.btn = btn self.root.mainloop() def start(self): self.progress.set(0) self.btn.config(state=tk.DISABLED) self.thread_queue = Queue.Queue() # used to communicate between main thread (UI) and worker thread new_thread = threading.Thread(target=self.run_loop, kwargs={'param1':100, 'param2':20}) new_thread.start() # schedule a time-task to check UI # it's in main thread, because it's called by self.root self.root.after(100, self.listen_for_result) def run_loop(self, param1, param2): progress = 0 for entry in range(self.progress_max): time.sleep(0.1) progress = progress + 1 self.thread_queue.put(progress) def listen_for_result(self): ''' Check if there is something in the queue. Must be invoked by self.root to be sure it's running in main thread ''' try: progress = self.thread_queue.get(False) self.progress.set(progress) except Queue.Empty: # must exist to avoid trace-back pass finally: if self.progress.get() < self.progressbar['maximum']: self.root.after(100, self.listen_for_result) else: self.btn.config(state=tk.NORMAL) if __name__ == '__main__': win = MainWindow() win.show()

一个进度条。设定最大进度为100。在子线程里每隔0.1秒更新一格。

总结

以上为个人经验,希望能给大家一个参考,也希望大家多多支持软件开发网。



Python 线程 多线程 tkinter

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