python tkinter实现弹窗的输入输出

Tesia ·
更新时间:2024-09-20
· 97 次阅读

本文实例为大家分享了python tkinter实现弹窗输入输出的具体代码,供大家参考,具体内容如下

代码如下:

from tkinter import * tk = Tk() tk.title('test') tk.geometry('350x350') #  输入框1 now_nub1 = Label(tk, text='1、请输入数字:') now_nub1.grid(row=1, column=1, sticky='E') now_bok1 = Spinbox(tk, values=[i for i in range(1, 999999)], width=5) now_bok1.grid(row=1, column=2, sticky='NW') #  输入框2 now_nub2 = Label(tk, text='2、请输入数字:') now_nub2.grid(row=2, column=1, sticky='E') now_bok2 = Spinbox(tk, values=[i for i in range(1, 999999)], width=5) now_bok2.grid(row=2, column=2, sticky='NW') #  输入框3 now_nub3 = Label(tk, text='3、请输入数字:') now_nub3.grid(row=3, column=1, sticky='E') now_bok3 = Spinbox(tk, values=[i for i in range(1, 999999)], width=5) now_bok3.grid(row=3, column=2, sticky='NW') #  输出结果 Output_results = Label(tk, text='输出结果:') Output_results.grid(row=8, column=1, sticky='NW') result_data_Text = Text(tk, width=20, height=10)  #处理结果展示 result_data_Text.grid(row=10, column=2, rowspan=15, columnspan=10) def value():     now_lis = [now_bok1.get(), now_bok2.get(), now_bok3.get()]     now_lis.sort()     result_data_Text = Label(tk, text='第一名:%s\n第二名:%s\n第三名:%s' % (now_lis[2], now_lis[1], now_lis[0]))     result_data_Text.grid(row=10, column=2, rowspan=15, columnspan=10) AnNiu = Button(tk, text='提交', fg='blue', bd=2, width=10, command=value) AnNiu.grid(row=5, column=2, sticky='NW') tk.mainloop()

结果如下:



弹窗 输出 输入 tkinter Python

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