《C程序设计语言》学习笔记——练习2-4

Chloe ·

更新时间:2024-11-11

· 620 次阅读

看了些网上的答案，对于不同长度的字符串，去掉相同字符后，得到的字符串不是很全。

#include

#define MAXLEN 100 //字符串长度为100，可以自己定义

int my_getline(char ch[] , int len); //把输入的字符，保存在字符数组中。
void my_squeeze(char ch1[] , char ch2[]); //把两个字符串进行对比，去掉相同字符

int main(void){
   char line1[MAXLEN];
   char line2[MAXLEN];
   int len1 = 0;
   int len2 = 0;

   while( (len1=my_getline(line1,MAXLEN)) > 0 && (len2=my_getline(line2,MAXLEN)) > 0 ){
       printf("over line1:%s , over line2:%s\n",line1,line2);
       my_squeeze(line1 , line2);
       printf("now line1:%s , now line2:%s\n",line1,line2);
   }
   return 0;
}

int my_getline(char line[] , int l){
int i = 0;
int c = 0;

   for(i = 0;i < MAXLEN-2 && (c = getchar()) != EOF && c != '\n';++i){ //-2是为了保存'\n'和'\0'
       line[i] = c;
   }
   if(c == '\n'){
       line[i] = c;
       ++i;
   }
   line[i] = '\0';

   return i;
}

void my_squeeze(char ch1[] , char ch2[]){
int i = 0 , j = 0 , t = 0;
int m = 0, n = 0;

   while(ch1[m] != '\0')
       m++;
   while(ch2[n] != '\0')
       n++;

   for(t = 0 ; ch1[t] != '\0' || ch2[t] != '\0'; t++){
       if(ch1[t] != ch2[t] && ch1[t] != '\0' && ch2[t] != '\0'){
           ch1[i++] = ch1[t];
           ch2[j++] = ch2[t];
       }
       else if(ch2[t] == '\0' && t < m-1){ //如果ch2比较短的话，ch1的字符直接顺序存储
           ch1[i++] = ch1[t];
       }
       else if(ch1[t] == '\0' && t < n-1){
           ch2[j++] = ch2[t];
       }
   }
   ch1[i] = '\0';
   ch2[j] = '\0';
}

作者：xiao586467

c程序设计语言 c程序设计 c程序学习笔记学习

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