本文实例讲述了C#图像边缘检测(Roberts)的方法。分享给大家供大家参考。具体如下:
//定义roberts算子函数
private static Bitmap robert(Bitmap a)
{
int w = a.Width;
int h = a.Height;
try
{
Bitmap dstBitmap = new Bitmap(w, h, System.Drawing.Imaging.PixelFormat.Format24bppRgb);
System.Drawing.Imaging.BitmapData srcData = a.LockBits(new Rectangle
(0, 0, w, h), System.Drawing.Imaging.ImageLockMode.ReadOnly, System.Drawing.Imaging.PixelFormat.Format24bppRgb);
System.Drawing.Imaging.BitmapData dstData = dstBitmap.LockBits(new Rectangle
(0, 0, w, h), System.Drawing.Imaging.ImageLockMode.WriteOnly, System.Drawing.Imaging.PixelFormat.Format24bppRgb);
unsafe
{
byte* pIn = (byte*)srcData.Scan0.ToPointer();
byte* pOut = (byte*)dstData.Scan0.ToPointer();
byte* p;
int stride = srcData.Stride;
for (int y = 0; y < h; y++)
{
for (int x = 0; x < w; x++)
{
//边缘八个点像素不变
if (x == 0 || x == w - 1 || y == 0 || y == h - 1)
{
pOut[0] = pIn[0];
pOut[1] = pIn[1];
pOut[2] = pIn[2];
}
else
{
int r0, r5, r6, r7;
int g5, g6, g7, g0;
int b5, b6, b7, b0;
double vR, vG, vB;
//右
p = pIn + 3;
r5 = p[2];
g5 = p[1];
b5 = p[0];
//左下
p = pIn + stride - 3;
r6 = p[2];
g6 = p[1];
b6 = p[0];
//正下
p = pIn + stride;
r7 = p[2];
g7 = p[1];
b7 = p[0];
//中心点
p = pIn;
r0 = p[2];
g0 = p[1];
b0 = p[0];
vR = (double)(Math .Abs (r0-r5)+Math .Abs ( r5-r7));
vG = (double)(Math.Abs(g0 - g5) + Math.Abs(g5 - g7));
vB = (double)(Math.Abs(b0 - b5) + Math.Abs(b5 - b7));
if (vR > 0)
{
vR = Math.Min(255, vR);
}
else
{
vR = Math.Max(0, vR);
}
if (vG > 0)
{
vG = Math.Min(255, vG);
}
else
{
vG = Math.Max(0, vG);
}
if (vB > 0)
{
vB = Math.Min(255, vB);
}
else
{
vB = Math.Max(0, vB);
}
pOut[0] = (byte)vB;
pOut[1] = (byte)vG;
pOut[2] = (byte)vR;
}
pIn += 3;
pOut += 3;
}
pIn += srcData.Stride - w * 3;
pOut += srcData.Stride - w * 3;
}
}
a.UnlockBits(srcData);
dstBitmap.UnlockBits(dstData);
return dstBitmap;
}
catch
{
return null;
}
}
希望本文所述对大家的C#程序设计有所帮助。
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