ajax提交到java后台之后处理数据的实现

Maren ·

更新时间:2024-09-21

· 543 次阅读

环境：eclipse+struts

要实现的效果：点击按钮提交数据到后台之后回到前台显示出来数据

index.jsp


<%@ page language="java" contentType="text/html; charset=UTF-8" 
  pageEncoding="UTF-8"%> 
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
<title>Insert title here</title> 
</head> 
<body> 
<input type="text" id="userinput"> 
<input type="button" id="submit"> 
<div id="msg"></div> 
</body> 
<script type="text/javascript" src="jquery-2.1.0.js"></script> 
<script type="text/javascript"> 
window.onload = function() { 
  document.getElementById("submit").onclick = test; 
} 
function test(){ 
  var userinput = document.getElementById("userinput"); 
  $.post("http://localhost:8080/TestSpring/TestAction",{username:userinput.value}, 
  function(data, textStatus){ 
    document.getElementById("msg").innerHTML = data; 
  });  
} 
</script> 
</html>

struts.xml


<action name="TestAction" class="com.action.Test"> 
  <result>index.jsp</result> 
</action>

Test.java


package com.action; 
import java.io.PrintWriter; 
import java.util.Map; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 
import org.apache.struts2.ServletActionContext; 
import com.opensymphony.xwork2.ActionContext; 
import com.opensymphony.xwork2.ActionSupport; 
public class Test extends ActionSupport { 
  @Override 
  public String execute() throws Exception { 
    // TODO Auto-generated method stub 
    HttpServletRequest request = org.apache.struts2.ServletActionContext.getRequest(); 
    HttpServletResponse response = ServletActionContext.getResponse(); 
    request.setCharacterEncoding("utf-8"); 
    response.setCharacterEncoding("utf-8"); 
    PrintWriter out = response.getWriter(); 
    out.write(request.getParameter("username")); 
    out.flush(); 
    out.close(); 
    return SUCCESS; 
  } 
}

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